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-2x^{2}+42=0
Add 36 and 6 to get 42.
-2x^{2}=-42
Subtract 42 from both sides. Anything subtracted from zero gives its negation.
x^{2}=\frac{-42}{-2}
Divide both sides by -2.
x^{2}=21
Divide -42 by -2 to get 21.
x=\sqrt{21} x=-\sqrt{21}
Take the square root of both sides of the equation.
-2x^{2}+42=0
Add 36 and 6 to get 42.
x=\frac{0±\sqrt{0^{2}-4\left(-2\right)\times 42}}{2\left(-2\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -2 for a, 0 for b, and 42 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-2\right)\times 42}}{2\left(-2\right)}
Square 0.
x=\frac{0±\sqrt{8\times 42}}{2\left(-2\right)}
Multiply -4 times -2.
x=\frac{0±\sqrt{336}}{2\left(-2\right)}
Multiply 8 times 42.
x=\frac{0±4\sqrt{21}}{2\left(-2\right)}
Take the square root of 336.
x=\frac{0±4\sqrt{21}}{-4}
Multiply 2 times -2.
x=-\sqrt{21}
Now solve the equation x=\frac{0±4\sqrt{21}}{-4} when ± is plus.
x=\sqrt{21}
Now solve the equation x=\frac{0±4\sqrt{21}}{-4} when ± is minus.
x=-\sqrt{21} x=\sqrt{21}
The equation is now solved.