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x\left(-2x+28\right)=0
Factor out x.
x=0 x=14
To find equation solutions, solve x=0 and -2x+28=0.
-2x^{2}+28x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-28±\sqrt{28^{2}}}{2\left(-2\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -2 for a, 28 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-28±28}{2\left(-2\right)}
Take the square root of 28^{2}.
x=\frac{-28±28}{-4}
Multiply 2 times -2.
x=\frac{0}{-4}
Now solve the equation x=\frac{-28±28}{-4} when ± is plus. Add -28 to 28.
x=0
Divide 0 by -4.
x=-\frac{56}{-4}
Now solve the equation x=\frac{-28±28}{-4} when ± is minus. Subtract 28 from -28.
x=14
Divide -56 by -4.
x=0 x=14
The equation is now solved.
-2x^{2}+28x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{-2x^{2}+28x}{-2}=\frac{0}{-2}
Divide both sides by -2.
x^{2}+\frac{28}{-2}x=\frac{0}{-2}
Dividing by -2 undoes the multiplication by -2.
x^{2}-14x=\frac{0}{-2}
Divide 28 by -2.
x^{2}-14x=0
Divide 0 by -2.
x^{2}-14x+\left(-7\right)^{2}=\left(-7\right)^{2}
Divide -14, the coefficient of the x term, by 2 to get -7. Then add the square of -7 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-14x+49=49
Square -7.
\left(x-7\right)^{2}=49
Factor x^{2}-14x+49. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-7\right)^{2}}=\sqrt{49}
Take the square root of both sides of the equation.
x-7=7 x-7=-7
Simplify.
x=14 x=0
Add 7 to both sides of the equation.