Solve for x
x=\frac{y}{2}+z-4
Solve for y
y=2\left(x-z+4\right)
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-2x+2z=8-y
Subtract y from both sides.
-2x=8-y-2z
Subtract 2z from both sides.
-2x=8-2z-y
The equation is in standard form.
\frac{-2x}{-2}=\frac{8-2z-y}{-2}
Divide both sides by -2.
x=\frac{8-2z-y}{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{y}{2}+z-4
Divide 8-y-2z by -2.
y+2z=8+2x
Add 2x to both sides.
y=8+2x-2z
Subtract 2z from both sides.
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Simultaneous equation
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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