Solve for x
x=\frac{3\left(y-2\right)}{2}
Solve for y
y=\frac{2\left(x+3\right)}{3}
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-2x=6-3y
Subtract 3y from both sides.
\frac{-2x}{-2}=\frac{6-3y}{-2}
Divide both sides by -2.
x=\frac{6-3y}{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{3y}{2}-3
Divide 6-3y by -2.
3y=6+2x
Add 2x to both sides.
3y=2x+6
The equation is in standard form.
\frac{3y}{3}=\frac{2x+6}{3}
Divide both sides by 3.
y=\frac{2x+6}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{2x}{3}+2
Divide 6+2x by 3.
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