Solve for x
x=\frac{3\left(y+6\right)}{2}
Solve for y
y=\frac{2\left(x-9\right)}{3}
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-2x=-18-3y
Subtract 3y from both sides.
-2x=-3y-18
The equation is in standard form.
\frac{-2x}{-2}=\frac{-3y-18}{-2}
Divide both sides by -2.
x=\frac{-3y-18}{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{3y}{2}+9
Divide -18-3y by -2.
3y=-18+2x
Add 2x to both sides.
3y=2x-18
The equation is in standard form.
\frac{3y}{3}=\frac{2x-18}{3}
Divide both sides by 3.
y=\frac{2x-18}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{2x}{3}-6
Divide -18+2x by 3.
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