Solve for x
x=\frac{3y+5z-1}{2}
Solve for y
y=\frac{2x-5z+1}{3}
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-2x+5z=1-3y
Subtract 3y from both sides.
-2x=1-3y-5z
Subtract 5z from both sides.
-2x=1-5z-3y
The equation is in standard form.
\frac{-2x}{-2}=\frac{1-5z-3y}{-2}
Divide both sides by -2.
x=\frac{1-5z-3y}{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{3y+5z-1}{2}
Divide 1-3y-5z by -2.
3y+5z=1+2x
Add 2x to both sides.
3y=1+2x-5z
Subtract 5z from both sides.
3y=2x-5z+1
The equation is in standard form.
\frac{3y}{3}=\frac{2x-5z+1}{3}
Divide both sides by 3.
y=\frac{2x-5z+1}{3}
Dividing by 3 undoes the multiplication by 3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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