Solve for x
x=y^{2}+2
Solve for y (complex solution)
y=-\sqrt{x-2}
y=\sqrt{x-2}
Solve for y
y=\sqrt{x-2}
y=-\sqrt{x-2}\text{, }x\geq 2
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x+2x-3y^{2}=2+4
Combine -2x and 3x to get x.
3x-3y^{2}=2+4
Combine x and 2x to get 3x.
3x-3y^{2}=6
Add 2 and 4 to get 6.
3x=6+3y^{2}
Add 3y^{2} to both sides.
3x=3y^{2}+6
The equation is in standard form.
\frac{3x}{3}=\frac{3y^{2}+6}{3}
Divide both sides by 3.
x=\frac{3y^{2}+6}{3}
Dividing by 3 undoes the multiplication by 3.
x=y^{2}+2
Divide 6+3y^{2} by 3.
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