Solve -2t^2+32

$$- 2 t ^ { 2 } + 32$$

Factor

$$2\left(-t-4\right)\left(t-4\right)$$

Solution Steps

Factor out 2.

$$2\left(-t^{2}+16\right)$$

Consider -t^{2}+16. Rewrite -t^{2}+16 as 4^{2}-t^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(4-t\right)\left(4+t\right)$$

Reorder the terms.

$$\left(-t+4\right)\left(t+4\right)$$

Rewrite the complete factored expression.

$$2\left(-t+4\right)\left(t+4\right)$$

Evaluate

$$32-2t^{2}$$