Solve for a
a=\frac{x-3b}{2}
Solve for b
b=\frac{x-2a}{3}
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-2a=3b-x
Subtract x from both sides.
\frac{-2a}{-2}=\frac{3b-x}{-2}
Divide both sides by -2.
a=\frac{3b-x}{-2}
Dividing by -2 undoes the multiplication by -2.
a=\frac{x-3b}{2}
Divide 3b-x by -2.
3b=-2a+x
Swap sides so that all variable terms are on the left hand side.
3b=x-2a
The equation is in standard form.
\frac{3b}{3}=\frac{x-2a}{3}
Divide both sides by 3.
b=\frac{x-2a}{3}
Dividing by 3 undoes the multiplication by 3.
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