Solve -2(y+6)+28<4(3-y)

$$- 2 ( y + 6 ) + 28 < 4 ( 3 - y )$$

Solve for y

$$y<-2$$

Solution Steps

Use the distributive property to multiply -2 by y+6.

$$-2y-12+28<4\left(3-y\right)$$

Add -12 and 28 to get 16.

$$-2y+16<4\left(3-y\right)$$

Use the distributive property to multiply 4 by 3-y.

$$-2y+16<12-4y$$

Add 4y to both sides.

$$-2y+16+4y<12$$

Combine -2y and 4y to get 2y.

$$2y+16<12$$

Subtract 16 from both sides.

$$2y<12-16$$

Subtract 16 from 12 to get -4.

$$2y<-4$$

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$y<\frac{-4}{2}$$

Divide -4 by 2 to get -2.

$$y<-2$$