Solve -2(x+2)=6-ax

$$- 2 ( x + 2 ) = 6 - a x$$

Solve for a

$$a=2+\frac{10}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply -2 by x+2.

$$-2x-4=6-ax$$

Swap sides so that all variable terms are on the left hand side.

$$6-ax=-2x-4$$

Subtract 6 from both sides.

$$-ax=-2x-4-6$$

Subtract 6 from -4 to get -10.

$$-ax=-2x-10$$

The equation is in standard form.

$$\left(-x\right)a=-2x-10$$

Divide both sides by -x.

$$\frac{\left(-x\right)a}{-x}=\frac{-2x-10}{-x}$$

Dividing by -x undoes the multiplication by -x.

$$a=\frac{-2x-10}{-x}$$

Divide -2x-10 by -x.

$$a=2+\frac{10}{x}$$

Solve for x

$$x=\frac{10}{a-2}$$

$$a\neq 2$$

Steps for Solving Linear Equation

Use the distributive property to multiply -2 by x+2.

$$-2x-4=6-ax$$

Add ax to both sides.

$$-2x-4+ax=6$$

Add 4 to both sides.

$$-2x+ax=6+4$$

Add 6 and 4 to get 10.

$$-2x+ax=10$$

Combine all terms containing x.

$$\left(-2+a\right)x=10$$

The equation is in standard form.

$$\left(a-2\right)x=10$$

Divide both sides by -2+a.

$$\frac{\left(a-2\right)x}{a-2}=\frac{10}{a-2}$$

Dividing by -2+a undoes the multiplication by -2+a.

$$x=\frac{10}{a-2}$$