Solve for t
t = \frac{85}{3} = 28\frac{1}{3} \approx 28.333333333
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-0.2\times 3t+10\times 3-80\times 0.1-5=0
Multiply -2 and 0.1 to get -0.2.
-0.6t+10\times 3-80\times 0.1-5=0
Multiply -0.2 and 3 to get -0.6.
-0.6t+30-80\times 0.1-5=0
Multiply 10 and 3 to get 30.
-0.6t+30-8-5=0
Multiply 80 and 0.1 to get 8.
-0.6t+22-5=0
Subtract 8 from 30 to get 22.
-0.6t+17=0
Subtract 5 from 22 to get 17.
-0.6t=-17
Subtract 17 from both sides. Anything subtracted from zero gives its negation.
t=\frac{-17}{-0.6}
Divide both sides by -0.6.
t=\frac{-170}{-6}
Expand \frac{-17}{-0.6} by multiplying both numerator and the denominator by 10.
t=\frac{85}{3}
Reduce the fraction \frac{-170}{-6} to lowest terms by extracting and canceling out -2.
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