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Solve for b
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Solve for t
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-2\times 5t+12b=48
Multiply both sides of the equation by 12.
-10t+12b=48
Multiply -2 and 5 to get -10.
12b=48+10t
Add 10t to both sides.
12b=10t+48
The equation is in standard form.
\frac{12b}{12}=\frac{10t+48}{12}
Divide both sides by 12.
b=\frac{10t+48}{12}
Dividing by 12 undoes the multiplication by 12.
b=\frac{5t}{6}+4
Divide 48+10t by 12.
-2\times 5t+12b=48
Multiply both sides of the equation by 12.
-10t+12b=48
Multiply -2 and 5 to get -10.
-10t=48-12b
Subtract 12b from both sides.
\frac{-10t}{-10}=\frac{48-12b}{-10}
Divide both sides by -10.
t=\frac{48-12b}{-10}
Dividing by -10 undoes the multiplication by -10.
t=\frac{6b-24}{5}
Divide 48-12b by -10.