Solve for b
b=-\frac{2}{c\sigma }
c\neq 0\text{ and }\sigma \neq 0
Solve for c
c=-\frac{2}{b\sigma }
b\neq 0\text{ and }\sigma \neq 0
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\left(-2c\sigma \right)b=4
The equation is in standard form.
\frac{\left(-2c\sigma \right)b}{-2c\sigma }=\frac{4}{-2c\sigma }
Divide both sides by -2\sigma c.
b=\frac{4}{-2c\sigma }
Dividing by -2\sigma c undoes the multiplication by -2\sigma c.
b=-\frac{2}{c\sigma }
Divide 4 by -2\sigma c.
\left(-2b\sigma \right)c=4
The equation is in standard form.
\frac{\left(-2b\sigma \right)c}{-2b\sigma }=\frac{4}{-2b\sigma }
Divide both sides by -2\sigma b.
c=\frac{4}{-2b\sigma }
Dividing by -2\sigma b undoes the multiplication by -2\sigma b.
c=-\frac{2}{b\sigma }
Divide 4 by -2\sigma b.
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