Solve -2quad3x+2/3=17/6

$$- 2 \quad \frac { 3 x + 2 } { 3 } = \frac { 17 } { 6 }$$

Solve for x

$$x = -\frac{25}{12} = -2\frac{1}{12} \approx -2.083333333$$

Steps for Solving Linear Equation

Divide both sides by -2.

$$\frac{3x+2}{3}=\frac{\frac{17}{6}}{-2}$$

Express \frac{\frac{17}{6}}{-2} as a single fraction.

$$\frac{3x+2}{3}=\frac{17}{6\left(-2\right)}$$

Multiply 6 and -2 to get -12.

$$\frac{3x+2}{3}=\frac{17}{-12}$$

Fraction \frac{17}{-12} can be rewritten as -\frac{17}{12} by extracting the negative sign.

$$\frac{3x+2}{3}=-\frac{17}{12}$$

Multiply both sides by 3.

$$3x+2=-\frac{17}{12}\times 3$$

Express -\frac{17}{12}\times 3 as a single fraction.

$$3x+2=\frac{-17\times 3}{12}$$

Multiply -17 and 3 to get -51.

$$3x+2=\frac{-51}{12}$$

Reduce the fraction \frac{-51}{12} to lowest terms by extracting and canceling out 3.

$$3x+2=-\frac{17}{4}$$

Subtract 2 from both sides.

$$3x=-\frac{17}{4}-2$$

Convert 2 to fraction \frac{8}{4}.

$$3x=-\frac{17}{4}-\frac{8}{4}$$

Since -\frac{17}{4} and \frac{8}{4} have the same denominator, subtract them by subtracting their numerators.

$$3x=\frac{-17-8}{4}$$

Subtract 8 from -17 to get -25.

$$3x=-\frac{25}{4}$$

Divide both sides by 3.

$$x=\frac{-\frac{25}{4}}{3}$$

Express \frac{-\frac{25}{4}}{3} as a single fraction.

$$x=\frac{-25}{4\times 3}$$

Multiply 4 and 3 to get 12.

$$x=\frac{-25}{12}$$

Fraction \frac{-25}{12} can be rewritten as -\frac{25}{12} by extracting the negative sign.

$$x=-\frac{25}{12}$$