Solve -2*02(25-t/40x)^2

$$- 2 \cdot 02 ( 25 \frac { - t } { 40 x } ) ^ { 2 }$$

Evaluate

$$0$$

Solution Steps

Multiply -2 and 0 to get 0.

$$0\times 2\times \left(25\times \frac{-t}{40x}\right)^{2}$$

Multiply 0 and 2 to get 0.

$$0\times \left(25\times \frac{-t}{40x}\right)^{2}$$

Express 25\times \frac{-t}{40x} as a single fraction.

$$0\times \left(\frac{25\left(-t\right)}{40x}\right)^{2}$$

Cancel out 5 in both numerator and denominator.

$$0\times \left(\frac{5\left(-t\right)}{8x}\right)^{2}$$

To raise \frac{5\left(-t\right)}{8x} to a power, raise both numerator and denominator to the power and then divide.

$$0\times \frac{\left(5\left(-t\right)\right)^{2}}{\left(8x\right)^{2}}$$

Anything times zero gives zero.

$$0$$

Factor

$$0$$