Solve -2^4-(-4)^2*(-1)+(-3)^2

$$- 2 ^ { 4 } - ( - 4 ) ^ { 2 } \times ( - 1 ) + ( - 3 ) ^ { 2 }$$

Evaluate

$$9$$

Solution Steps

Calculate 2 to the power of 4 and get 16.

$$-16-\left(-4\right)^{2}\left(-1\right)+\left(-3\right)^{2}$$

Calculate -4 to the power of 2 and get 16.

$$-16-16\left(-1\right)+\left(-3\right)^{2}$$

Multiply 16 and -1 to get -16.

$$-16-\left(-16\right)+\left(-3\right)^{2}$$

The opposite of -16 is 16.

$$-16+16+\left(-3\right)^{2}$$

Add -16 and 16 to get 0.

$$0+\left(-3\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$0+9$$

Add 0 and 9 to get 9.

$$9$$

Factor

$$3^{2}$$