Solve -2^4*2^3quadf)

$$- 2 ^ { 4 } \cdot 2 ^ { 3 } \quad f )$$

Evaluate

$$-128f$$

Solution Steps

Calculate 2 to the power of 4 and get 16.

$$-16\times 2^{3}f$$

Calculate 2 to the power of 3 and get 8.

$$-16\times 8f$$

Multiply -16 and 8 to get -128.

$$-128f$$

Differentiate w.r.t. f

$$-128$$

Steps Using Definition of a Derivative

Calculate 2 to the power of 4 and get 16.

$$\frac{\mathrm{d}}{\mathrm{d}f}(-16\times 2^{3}f)$$

Calculate 2 to the power of 3 and get 8.

$$\frac{\mathrm{d}}{\mathrm{d}f}(-16\times 8f)$$

Multiply -16 and 8 to get -128.

$$\frac{\mathrm{d}}{\mathrm{d}f}(-128f)$$

The derivative of ax^{n} is nax^{n-1}.

$$-128f^{1-1}$$

Subtract 1 from 1.

$$-128f^{0}$$

For any term t except 0, t^{0}=1.

$$-128$$