Solve -2^4+(3-7)^2-|2*(-1)^3|

$$- 2 ^ { 4 } + ( 3 - 7 ) ^ { 2 } - | 2 \times ( - 1 ) ^ { 3 } |$$

Evaluate

$$-2$$

Solution Steps

Calculate 2 to the power of 4 and get 16.

$$-16+\left(3-7\right)^{2}-|2\left(-1\right)^{3}|$$

Subtract 7 from 3 to get -4.

$$-16+\left(-4\right)^{2}-|2\left(-1\right)^{3}|$$

Calculate -4 to the power of 2 and get 16.

$$-16+16-|2\left(-1\right)^{3}|$$

Add -16 and 16 to get 0.

$$0-|2\left(-1\right)^{3}|$$

Calculate -1 to the power of 3 and get -1.

$$0-|2\left(-1\right)|$$

Multiply 2 and -1 to get -2.

$$0-|-2|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -2 is 2.

$$0-2$$

Subtract 2 from 0 to get -2.

$$-2$$

Factor

$$-2$$