Solve -2^3-(2a-3)*2^2+4*(-2)-2=0

$$- 2 ^ { 3 } - ( 2 a - 3 ) \cdot 2 ^ { 2 } + 4 \cdot ( - 2 ) - 2 = 0$$

Solve for a

$$a=-\frac{3}{4}=-0.75$$

Steps for Solving Linear Equation

Calculate 2 to the power of 3 and get 8.

$$-8-\left(2a-3\right)\times 2^{2}+4\left(-2\right)-2=0$$

Calculate 2 to the power of 2 and get 4.

$$-8-\left(2a-3\right)\times 4+4\left(-2\right)-2=0$$

Use the distributive property to multiply 2a-3 by 4.

$$-8-\left(8a-12\right)+4\left(-2\right)-2=0$$

To find the opposite of 8a-12, find the opposite of each term.

$$-8-8a-\left(-12\right)+4\left(-2\right)-2=0$$

The opposite of -12 is 12.

$$-8-8a+12+4\left(-2\right)-2=0$$

Add -8 and 12 to get 4.

$$4-8a+4\left(-2\right)-2=0$$

Multiply 4 and -2 to get -8.

$$4-8a-8-2=0$$

Subtract 8 from 4 to get -4.

$$-4-8a-2=0$$

Subtract 2 from -4 to get -6.

$$-6-8a=0$$

Add 6 to both sides. Anything plus zero gives itself.

$$-8a=6$$

Divide both sides by -8.

$$a=\frac{6}{-8}$$

Reduce the fraction \frac{6}{-8} to lowest terms by extracting and canceling out 2.

$$a=-\frac{3}{4}$$