Solve -2^3div(-4/3)-(-3)^2*(-1)^2019

$$- 2 ^ { 3 } \div ( - \frac { 4 } { 3 } ) - ( - 3 ) ^ { 2 } \times ( - 1 ) ^ { 2019 }$$

Evaluate

$$15$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{-8}{-\frac{4}{3}}-\left(-3\right)^{2}\left(-1\right)^{2019}$$

Divide -8 by -\frac{4}{3} by multiplying -8 by the reciprocal of -\frac{4}{3}.

$$-8\left(-\frac{3}{4}\right)-\left(-3\right)^{2}\left(-1\right)^{2019}$$

Express -8\left(-\frac{3}{4}\right) as a single fraction.

$$\frac{-8\left(-3\right)}{4}-\left(-3\right)^{2}\left(-1\right)^{2019}$$

Multiply -8 and -3 to get 24.

$$\frac{24}{4}-\left(-3\right)^{2}\left(-1\right)^{2019}$$

Divide 24 by 4 to get 6.

$$6-\left(-3\right)^{2}\left(-1\right)^{2019}$$

Calculate -3 to the power of 2 and get 9.

$$6-9\left(-1\right)^{2019}$$

Calculate -1 to the power of 2019 and get -1.

$$6-9\left(-1\right)$$

Multiply 9 and -1 to get -9.

$$6-\left(-9\right)$$

The opposite of -9 is 9.

$$6+9$$

Add 6 and 9 to get 15.

$$15$$

Factor

$$3\times 5$$