Solve -2^3+(-2)^2*(-1)-(-2)^4div(-2)^3

$$- 2 ^ { 3 } + ( - 2 ) ^ { 2 } \times ( - 1 ) - ( - 2 ) ^ { 4 } \div ( - 2 ) ^ { 3 }$$

Evaluate

$$-10$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 3 from 4 to get 1.

$$-2^{3}+\left(-2\right)^{2}\left(-1\right)-\left(-2\right)^{1}$$

Calculate 2 to the power of 3 and get 8.

$$-8+\left(-2\right)^{2}\left(-1\right)-\left(-2\right)^{1}$$

Calculate -2 to the power of 2 and get 4.

$$-8+4\left(-1\right)-\left(-2\right)^{1}$$

Multiply 4 and -1 to get -4.

$$-8-4-\left(-2\right)^{1}$$

Subtract 4 from -8 to get -12.

$$-12-\left(-2\right)^{1}$$

Calculate -2 to the power of 1 and get -2.

$$-12-\left(-2\right)$$

The opposite of -2 is 2.

$$-12+2$$

Add -12 and 2 to get -10.

$$-10$$

Factor

$$-10$$