Solve -2^3+1/3*(2017+3)^0-(1/3)^-2

$$- 2 ^ { 3 } + \frac { 1 } { 3 } \times ( 2017 + 3 ) ^ { 0 } - ( \frac { 1 } { 3 } ) ^ { - 2 }$$

Evaluate

$$-\frac{50}{3}\approx -16.666666667$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$-8+\frac{1}{3}\left(2017+3\right)^{0}-\left(\frac{1}{3}\right)^{-2}$$

Add 2017 and 3 to get 2020.

$$-8+\frac{1}{3}\times 2020^{0}-\left(\frac{1}{3}\right)^{-2}$$

Calculate 2020 to the power of 0 and get 1.

$$-8+\frac{1}{3}\times 1-\left(\frac{1}{3}\right)^{-2}$$

Multiply \frac{1}{3} and 1 to get \frac{1}{3}.

$$-8+\frac{1}{3}-\left(\frac{1}{3}\right)^{-2}$$

Add -8 and \frac{1}{3} to get -\frac{23}{3}.

$$-\frac{23}{3}-\left(\frac{1}{3}\right)^{-2}$$

Calculate \frac{1}{3} to the power of -2 and get 9.

$$-\frac{23}{3}-9$$

Subtract 9 from -\frac{23}{3} to get -\frac{50}{3}.

$$-\frac{50}{3}$$

Factor

$$-\frac{50}{3} = -16\frac{2}{3} = -16.666666666666668$$