Solve -2^3+1/3*(201+3)^0-(-1/3)^-2

$$- 2 ^ { 3 } + \frac { 1 } { 3 } \times ( 201 + 3 ) ^ { 0 } - ( - \frac { 1 } { 3 } ) ^ { - 2 }$$

Evaluate

$$-\frac{50}{3}\approx -16.666666667$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$-8+\frac{1}{3}\left(201+3\right)^{0}-\left(-\frac{1}{3}\right)^{-2}$$

Add 201 and 3 to get 204.

$$-8+\frac{1}{3}\times 204^{0}-\left(-\frac{1}{3}\right)^{-2}$$

Calculate 204 to the power of 0 and get 1.

$$-8+\frac{1}{3}\times 1-\left(-\frac{1}{3}\right)^{-2}$$

Multiply \frac{1}{3} and 1 to get \frac{1}{3}.

$$-8+\frac{1}{3}-\left(-\frac{1}{3}\right)^{-2}$$

Add -8 and \frac{1}{3} to get -\frac{23}{3}.

$$-\frac{23}{3}-\left(-\frac{1}{3}\right)^{-2}$$

Calculate -\frac{1}{3} to the power of -2 and get 9.

$$-\frac{23}{3}-9$$

Subtract 9 from -\frac{23}{3} to get -\frac{50}{3}.

$$-\frac{50}{3}$$

Factor

$$-\frac{50}{3} = -16\frac{2}{3} = -16.666666666666668$$