Solve -2^{2}-(-2)^2-2^3+(-2)^3+[-(-2)]^3

$$- 2 ^ { 2 } - ( - 2 ) ^ { 2 } - 2 ^ { 3 } + ( - 2 ) ^ { 3 } + [ - ( - 2 ) ] ^ { 3 }$$

Evaluate

$$-16$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-4-\left(-2\right)^{2}-2^{3}+\left(-2\right)^{3}+\left(-\left(-2\right)\right)^{3}$$

Calculate -2 to the power of 2 and get 4.

$$-4-4-2^{3}+\left(-2\right)^{3}+\left(-\left(-2\right)\right)^{3}$$

Subtract 4 from -4 to get -8.

$$-8-2^{3}+\left(-2\right)^{3}+\left(-\left(-2\right)\right)^{3}$$

Calculate 2 to the power of 3 and get 8.

$$-8-8+\left(-2\right)^{3}+\left(-\left(-2\right)\right)^{3}$$

Subtract 8 from -8 to get -16.

$$-16+\left(-2\right)^{3}+\left(-\left(-2\right)\right)^{3}$$

Calculate -2 to the power of 3 and get -8.

$$-16-8+\left(-\left(-2\right)\right)^{3}$$

Subtract 8 from -16 to get -24.

$$-24+\left(-\left(-2\right)\right)^{3}$$

The opposite of -2 is 2.

$$-24+2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$-24+8$$

Add -24 and 8 to get -16.

$$-16$$

Factor

$$-16$$