Solve -2^2(2^3div2^1)-2^3

$$- 2 ^ { 2 } ( 2 ^ { 3 } \div 2 ^ { 1 } ) - 2 ^ { 3 }$$

Evaluate

$$-24$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 3 to get 2.

$$\left(-2^{2}\right)\times 2^{2}-2^{3}$$

Calculate 2 to the power of 2 and get 4.

$$-4\times 2^{2}-2^{3}$$

Calculate 2 to the power of 2 and get 4.

$$-4\times 4-2^{3}$$

Multiply -4 and 4 to get -16.

$$-16-2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$-16-8$$

Subtract 8 from -16 to get -24.

$$-24$$

Factor

$$-24$$