Solve -2^2*|-1/2|+8div(-2)^3

$$- 2 ^ { 2 } \times | - \frac { 1 } { 2 } | + 8 \div ( - 2 ) ^ { 3 }$$

Evaluate

$$-3$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-4|-\frac{1}{2}|+\frac{8}{\left(-2\right)^{3}}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -\frac{1}{2} is \frac{1}{2}.

$$-4\times \frac{1}{2}+\frac{8}{\left(-2\right)^{3}}$$

Multiply -4 and \frac{1}{2} to get \frac{-4}{2}.

$$\frac{-4}{2}+\frac{8}{\left(-2\right)^{3}}$$

Divide -4 by 2 to get -2.

$$-2+\frac{8}{\left(-2\right)^{3}}$$

Calculate -2 to the power of 3 and get -8.

$$-2+\frac{8}{-8}$$

Divide 8 by -8 to get -1.

$$-2-1$$

Subtract 1 from -2 to get -3.

$$-3$$

Factor

$$-3$$