Solve -2^2+2-2*-1+-1^2

$$- 2 ^ { 2 } + 2 - 2 \cdot - 1 + - 1 ^ { 2 }$$

Evaluate

$$-1$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-4+2-2\left(-1\right)-1^{2}$$

Add -4 and 2 to get -2.

$$-2-2\left(-1\right)-1^{2}$$

Multiply 2 and -1 to get -2.

$$-2-\left(-2\right)-1^{2}$$

The opposite of -2 is 2.

$$-2+2-1^{2}$$

Add -2 and 2 to get 0.

$$0-1^{2}$$

Calculate 1 to the power of 2 and get 1.

$$0-1$$

Subtract 1 from 0 to get -1.

$$-1$$

Factor

$$-1$$