Solve -2^2+(1/3)^-1-2cos60^circ+|-3|

$$- 2 ^ { 2 } + ( \frac { 1 } { 3 } ) ^ { - 1 } - 2 \cos 60 ^ { \circ } + | - 3 |$$

Evaluate

$$1$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-4+\left(\frac{1}{3}\right)^{-1}-2\cos(60)+|-3|$$

Calculate \frac{1}{3} to the power of -1 and get 3.

$$-4+3-2\cos(60)+|-3|$$

Add -4 and 3 to get -1.

$$-1-2\cos(60)+|-3|$$

Get the value of \cos(60) from trigonometric values table.

$$-1-2\times \frac{1}{2}+|-3|$$

Multiply 2 and \frac{1}{2} to get 1.

$$-1-1+|-3|$$

Subtract 1 from -1 to get -2.

$$-2+|-3|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.

$$-2+3$$

Add -2 and 3 to get 1.

$$1$$