Solve -2^2+sqrt{4}-sqrt[3]{28/2}*3+2(sqrt{3}-1)

$$- 2 ^ { 2 } + \sqrt { 4 } - \sqrt[ 3 ] { 2 \frac { 8 } { 2 } } \times 3 + 2 ( \sqrt { 3 } - 1 )$$

Evaluate

$$2\sqrt{3}-3\sqrt[3]{6}-4\approx -5.987260163$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-4+\sqrt{4}-\sqrt[3]{\frac{2\times 2+8}{2}}\times 3+2\left(\sqrt{3}-1\right)$$

Calculate the square root of 4 and get 2.

$$-4+2-\sqrt[3]{\frac{2\times 2+8}{2}}\times 3+2\left(\sqrt{3}-1\right)$$

Add -4 and 2 to get -2.

$$-2-\sqrt[3]{\frac{2\times 2+8}{2}}\times 3+2\left(\sqrt{3}-1\right)$$

Multiply 2 and 2 to get 4.

$$-2-\sqrt[3]{\frac{4+8}{2}}\times 3+2\left(\sqrt{3}-1\right)$$

Add 4 and 8 to get 12.

$$-2-\sqrt[3]{\frac{12}{2}}\times 3+2\left(\sqrt{3}-1\right)$$

Divide 12 by 2 to get 6.

$$-2-\sqrt[3]{6}\times 3+2\left(\sqrt{3}-1\right)$$

Use the distributive property to multiply 2 by \sqrt{3}-1.

$$-2-\sqrt[3]{6}\times 3+2\sqrt{3}-2$$

Multiply -1 and 3 to get -3.

$$-2-3\sqrt[3]{6}+2\sqrt{3}-2$$

Subtract 2 from -2 to get -4.

$$-4-3\sqrt[3]{6}+2\sqrt{3}$$