Solve -2^-1*(-2^-1)*(-2^-1)*(-2^4)=

$$- 2 ^ { - 1 } \cdot ( - 2 ^ { - 1 } ) \cdot ( - 2 ^ { - 1 } ) \cdot ( - 2 ^ { 4 } ) =$$

Evaluate

$$2$$

Solution Steps

Multiply -2^{-1} and -2^{-1} to get \left(-2^{-1}\right)^{2}.

$$\left(-2^{-1}\right)^{2}\left(-2^{-1}\right)\left(-2^{4}\right)$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\left(-2^{-1}\right)^{3}\left(-2^{4}\right)$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$\left(-\frac{1}{2}\right)^{3}\left(-2^{4}\right)$$

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$-\frac{1}{8}\left(-2^{4}\right)$$

Calculate 2 to the power of 4 and get 16.

$$-\frac{1}{8}\left(-16\right)$$

Multiply -\frac{1}{8} and -16 to get 2.

$$2$$

Factor

$$2$$