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\frac{-18}{-98}=d^{2}
Divide both sides by -98.
\frac{9}{49}=d^{2}
Reduce the fraction \frac{-18}{-98} to lowest terms by extracting and canceling out -2.
d^{2}=\frac{9}{49}
Swap sides so that all variable terms are on the left hand side.
d^{2}-\frac{9}{49}=0
Subtract \frac{9}{49} from both sides.
49d^{2}-9=0
Multiply both sides by 49.
\left(7d-3\right)\left(7d+3\right)=0
Consider 49d^{2}-9. Rewrite 49d^{2}-9 as \left(7d\right)^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
d=\frac{3}{7} d=-\frac{3}{7}
To find equation solutions, solve 7d-3=0 and 7d+3=0.
\frac{-18}{-98}=d^{2}
Divide both sides by -98.
\frac{9}{49}=d^{2}
Reduce the fraction \frac{-18}{-98} to lowest terms by extracting and canceling out -2.
d^{2}=\frac{9}{49}
Swap sides so that all variable terms are on the left hand side.
d=\frac{3}{7} d=-\frac{3}{7}
Take the square root of both sides of the equation.
\frac{-18}{-98}=d^{2}
Divide both sides by -98.
\frac{9}{49}=d^{2}
Reduce the fraction \frac{-18}{-98} to lowest terms by extracting and canceling out -2.
d^{2}=\frac{9}{49}
Swap sides so that all variable terms are on the left hand side.
d^{2}-\frac{9}{49}=0
Subtract \frac{9}{49} from both sides.
d=\frac{0±\sqrt{0^{2}-4\left(-\frac{9}{49}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{9}{49} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
d=\frac{0±\sqrt{-4\left(-\frac{9}{49}\right)}}{2}
Square 0.
d=\frac{0±\sqrt{\frac{36}{49}}}{2}
Multiply -4 times -\frac{9}{49}.
d=\frac{0±\frac{6}{7}}{2}
Take the square root of \frac{36}{49}.
d=\frac{3}{7}
Now solve the equation d=\frac{0±\frac{6}{7}}{2} when ± is plus.
d=-\frac{3}{7}
Now solve the equation d=\frac{0±\frac{6}{7}}{2} when ± is minus.
d=\frac{3}{7} d=-\frac{3}{7}
The equation is now solved.