Solve -16x^{2}y^3div(-4x^3y)*2x^4y^2

$$- 16 x ^ { 2 } y ^ { 3 } \div ( - 4 x ^ { 3 } y ) \times 2 x ^ { 4 } y ^ { 2 }$$

Evaluate

$$8x^{3}y^{4}$$

Solution Steps

Cancel out 4yx^{2} in both numerator and denominator.

$$\frac{-4y^{2}}{-x}\times 2x^{4}y^{2}$$

Cancel out -1 in both numerator and denominator.

$$\frac{4y^{2}}{x}\times 2x^{4}y^{2}$$

Express \frac{4y^{2}}{x}\times 2 as a single fraction.

$$\frac{4y^{2}\times 2}{x}x^{4}y^{2}$$

Express \frac{4y^{2}\times 2}{x}x^{4} as a single fraction.

$$\frac{4y^{2}\times 2x^{4}}{x}y^{2}$$

Cancel out x in both numerator and denominator.

$$2\times 4y^{2}x^{3}y^{2}$$

Multiply 2 and 4 to get 8.

$$8y^{2}x^{3}y^{2}$$

To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.

$$8y^{4}x^{3}$$

Differentiate w.r.t. x

$$24x^{2}y^{4}$$