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-16t^{2}=-146
Subtract 146 from both sides. Anything subtracted from zero gives its negation.
t^{2}=\frac{-146}{-16}
Divide both sides by -16.
t^{2}=\frac{73}{8}
Reduce the fraction \frac{-146}{-16} to lowest terms by extracting and canceling out -2.
t=\frac{\sqrt{146}}{4} t=-\frac{\sqrt{146}}{4}
Take the square root of both sides of the equation.
-16t^{2}+146=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
t=\frac{0±\sqrt{0^{2}-4\left(-16\right)\times 146}}{2\left(-16\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -16 for a, 0 for b, and 146 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
t=\frac{0±\sqrt{-4\left(-16\right)\times 146}}{2\left(-16\right)}
Square 0.
t=\frac{0±\sqrt{64\times 146}}{2\left(-16\right)}
Multiply -4 times -16.
t=\frac{0±\sqrt{9344}}{2\left(-16\right)}
Multiply 64 times 146.
t=\frac{0±8\sqrt{146}}{2\left(-16\right)}
Take the square root of 9344.
t=\frac{0±8\sqrt{146}}{-32}
Multiply 2 times -16.
t=-\frac{\sqrt{146}}{4}
Now solve the equation t=\frac{0±8\sqrt{146}}{-32} when ± is plus.
t=\frac{\sqrt{146}}{4}
Now solve the equation t=\frac{0±8\sqrt{146}}{-32} when ± is minus.
t=-\frac{\sqrt{146}}{4} t=\frac{\sqrt{146}}{4}
The equation is now solved.