Solve -16div[(-2)^3*(-2)]-[(-3)^2div(-9)]=

$$- 16 \div [ ( - 2 ) ^ { 3 } \cdot ( - 2 ) ] - [ ( - 3 ) ^ { 2 } \div ( - 9 ) ] =$$

Evaluate

$$0$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$\frac{-16}{\left(-2\right)^{4}}-\frac{\left(-3\right)^{2}}{-9}$$

Calculate -2 to the power of 4 and get 16.

$$\frac{-16}{16}-\frac{\left(-3\right)^{2}}{-9}$$

Divide -16 by 16 to get -1.

$$-1-\frac{\left(-3\right)^{2}}{-9}$$

Calculate -3 to the power of 2 and get 9.

$$-1-\frac{9}{-9}$$

Divide 9 by -9 to get -1.

$$-1-\left(-1\right)$$

The opposite of -1 is 1.

$$-1+1$$

Add -1 and 1 to get 0.

$$0$$

Factor

$$0$$