Solve -13-2b-b-7

$$- 13 - 2 b - b - 7$$

Evaluate

$$-3b-20$$

Solution Steps

Combine -2b and -b to get -3b.

$$-13-3b-7$$

Subtract 7 from -13 to get -20.

$$-20-3b$$

Differentiate w.r.t. b

$$-3$$

Steps Using Derivative Rule for Sum

Combine -2b and -b to get -3b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-13-3b-7)$$

Subtract 7 from -13 to get -20.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-20-3b)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-3b^{1-1}$$

Subtract 1 from 1.

$$-3b^{0}$$

For any term t except 0, t^{0}=1.

$$-3$$