Solve -131/3a*(1/40b)*1/3*(-6)=

$$- 13 \frac { 1 } { 3 } a \cdot ( \frac { 1 } { 40 } b ) \cdot \frac { 1 } { 3 } \cdot ( - 6 ) =$$

Evaluate

$$\frac{2ab}{3}$$

Solution Steps

Multiply 13 and 3 to get 39.

$$\left(-\frac{39+1}{3}\right)a\times \frac{1}{40}b\times \frac{1}{3}\left(-6\right)$$

Add 39 and 1 to get 40.

$$-\frac{40}{3}a\times \frac{1}{40}b\times \frac{1}{3}\left(-6\right)$$

Multiply -\frac{40}{3} times \frac{1}{40} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-40}{3\times 40}ab\times \frac{1}{3}\left(-6\right)$$

Do the multiplications in the fraction \frac{-40}{3\times 40}.

$$\frac{-40}{120}ab\times \frac{1}{3}\left(-6\right)$$

Reduce the fraction \frac{-40}{120} to lowest terms by extracting and canceling out 40.

$$-\frac{1}{3}ab\times \frac{1}{3}\left(-6\right)$$

Multiply -\frac{1}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-1}{3\times 3}ab\left(-6\right)$$

Do the multiplications in the fraction \frac{-1}{3\times 3}.

$$\frac{-1}{9}ab\left(-6\right)$$

Fraction \frac{-1}{9} can be rewritten as -\frac{1}{9} by extracting the negative sign.

$$-\frac{1}{9}ab\left(-6\right)$$

Express -\frac{1}{9}\left(-6\right) as a single fraction.

$$\frac{-\left(-6\right)}{9}ab$$

Multiply -1 and -6 to get 6.

$$\frac{6}{9}ab$$

Reduce the fraction \frac{6}{9} to lowest terms by extracting and canceling out 3.

$$\frac{2}{3}ab$$

Expand

$$\frac{2ab}{3}$$

Solution Steps

Multiply 13 and 3 to get 39.

$$\left(-\frac{39+1}{3}\right)a\times \frac{1}{40}b\times \frac{1}{3}\left(-6\right)$$

Add 39 and 1 to get 40.

$$-\frac{40}{3}a\times \frac{1}{40}b\times \frac{1}{3}\left(-6\right)$$

Multiply -\frac{40}{3} times \frac{1}{40} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-40}{3\times 40}ab\times \frac{1}{3}\left(-6\right)$$

Do the multiplications in the fraction \frac{-40}{3\times 40}.

$$\frac{-40}{120}ab\times \frac{1}{3}\left(-6\right)$$

Reduce the fraction \frac{-40}{120} to lowest terms by extracting and canceling out 40.

$$-\frac{1}{3}ab\times \frac{1}{3}\left(-6\right)$$

Multiply -\frac{1}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-1}{3\times 3}ab\left(-6\right)$$

Do the multiplications in the fraction \frac{-1}{3\times 3}.

$$\frac{-1}{9}ab\left(-6\right)$$

Fraction \frac{-1}{9} can be rewritten as -\frac{1}{9} by extracting the negative sign.

$$-\frac{1}{9}ab\left(-6\right)$$

Express -\frac{1}{9}\left(-6\right) as a single fraction.

$$\frac{-\left(-6\right)}{9}ab$$

Multiply -1 and -6 to get 6.

$$\frac{6}{9}ab$$

Reduce the fraction \frac{6}{9} to lowest terms by extracting and canceling out 3.

$$\frac{2}{3}ab$$