Solve -122<-3(-2-8x)-8x?

$$- 122 < - 3 ( - 2 - 8 x ) - 8 x ?$$

Solve for x

$$x>-8$$

Solution Steps

Use the distributive property to multiply -3 by -2-8x.

$$-122<6+24x-8x$$

Combine 24x and -8x to get 16x.

$$-122<6+16x$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$6+16x>-122$$

Subtract 6 from both sides.

$$16x>-122-6$$

Subtract 6 from -122 to get -128.

$$16x>-128$$

Divide both sides by 16. Since 16 is positive, the inequality direction remains the same.

$$x>\frac{-128}{16}$$

Divide -128 by 16 to get -8.

$$x>-8$$