Solve for c
\left\{\begin{matrix}c=-\frac{xz}{2m}\text{, }&m\neq 0\\c\in \mathrm{R}\text{, }&\left(x=0\text{ or }z=0\right)\text{ and }m=0\end{matrix}\right.
Solve for m
\left\{\begin{matrix}m=-\frac{xz}{2c}\text{, }&c\neq 0\\m\in \mathrm{R}\text{, }&\left(x=0\text{ or }z=0\right)\text{ and }c=0\end{matrix}\right.
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24cm=-12xz
Swap sides so that all variable terms are on the left hand side.
24mc=-12xz
The equation is in standard form.
\frac{24mc}{24m}=-\frac{12xz}{24m}
Divide both sides by 24m.
c=-\frac{12xz}{24m}
Dividing by 24m undoes the multiplication by 24m.
c=-\frac{xz}{2m}
Divide -12xz by 24m.
24cm=-12xz
Swap sides so that all variable terms are on the left hand side.
\frac{24cm}{24c}=-\frac{12xz}{24c}
Divide both sides by 24c.
m=-\frac{12xz}{24c}
Dividing by 24c undoes the multiplication by 24c.
m=-\frac{xz}{2c}
Divide -12xz by 24c.
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