Solve -12x^4y^3div(-x)*4xyquade

$$- 12 x ^ { 4 } y ^ { 3 } \div ( - x ) \times 4 x y \quad e$$

Evaluate

$$48e\left(xy\right)^{4}$$

Solution Steps

Express \frac{-12x^{4}y^{3}}{-x}\times 4 as a single fraction.

$$\frac{-12x^{4}y^{3}\times 4}{-x}xye$$

Express \frac{-12x^{4}y^{3}\times 4}{-x}x as a single fraction.

$$\frac{-12x^{4}y^{3}\times 4x}{-x}ye$$

Express \frac{-12x^{4}y^{3}\times 4x}{-x}y as a single fraction.

$$\frac{-12x^{4}y^{3}\times 4xy}{-x}e$$

Express \frac{-12x^{4}y^{3}\times 4xy}{-x}e as a single fraction.

$$\frac{-12x^{4}y^{3}\times 4xye}{-x}$$

To multiply powers of the same base, add their exponents. Add 4 and 1 to get 5.

$$\frac{-12x^{5}y^{3}\times 4ye}{-x}$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$\frac{-12x^{5}y^{4}\times 4e}{-x}$$

Multiply -12 and 4 to get -48.

$$\frac{-48x^{5}y^{4}e}{-x}$$

Cancel out x in both numerator and denominator.

$$\frac{-48ex^{4}y^{4}}{-1}$$

Anything divided by -1 gives its opposite.

$$48ex^{4}y^{4}$$

Differentiate w.r.t. x

$$192ex^{3}y^{4}$$