Solve -12(-4y/15+1/3)+40y=4

$$- 12 ( \frac { - 4 y } { 15 } + \frac { 1 } { 3 } ) + 40 y = 4$$

Solve for y

$$y=\frac{5}{27}\approx 0.185185185$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 15, the least common multiple of 15,3.

$$-180\left(\frac{-4y}{15}+\frac{1}{3}\right)+600y=60$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 15 and 3 is 15. Multiply \frac{1}{3} times \frac{5}{5}.

$$-180\left(\frac{-4y}{15}+\frac{5}{15}\right)+600y=60$$

Since \frac{-4y}{15} and \frac{5}{15} have the same denominator, add them by adding their numerators.

$$-180\times \frac{-4y+5}{15}+600y=60$$

Cancel out 15, the greatest common factor in 180 and 15.

$$-12\left(-4y+5\right)+600y=60$$

Use the distributive property to multiply -12 by -4y+5.

$$48y-60+600y=60$$

Combine 48y and 600y to get 648y.

$$648y-60=60$$

Add 60 to both sides.

$$648y=60+60$$

Add 60 and 60 to get 120.

$$648y=120$$

Divide both sides by 648.

$$y=\frac{120}{648}$$

Reduce the fraction \frac{120}{648} to lowest terms by extracting and canceling out 24.

$$y=\frac{5}{27}$$