Solve for x
x\leq -\frac{19}{8}
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8x+7\leq -12
Swap sides so that all variable terms are on the left hand side. This changes the sign direction.
8x\leq -12-7
Subtract 7 from both sides.
8x\leq -19
Subtract 7 from -12 to get -19.
x\leq -\frac{19}{8}
Divide both sides by 8. Since 8 is positive, the inequality direction remains the same.
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