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11\left(-x^{3}+7x^{2}-12x\right)
Factor out 11.
x\left(-x^{2}+7x-12\right)
Consider -x^{3}+7x^{2}-12x. Factor out x.
a+b=7 ab=-\left(-12\right)=12
Consider -x^{2}+7x-12. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx-12. To find a and b, set up a system to be solved.
1,12 2,6 3,4
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 12.
1+12=13 2+6=8 3+4=7
Calculate the sum for each pair.
a=4 b=3
The solution is the pair that gives sum 7.
\left(-x^{2}+4x\right)+\left(3x-12\right)
Rewrite -x^{2}+7x-12 as \left(-x^{2}+4x\right)+\left(3x-12\right).
-x\left(x-4\right)+3\left(x-4\right)
Factor out -x in the first and 3 in the second group.
\left(x-4\right)\left(-x+3\right)
Factor out common term x-4 by using distributive property.
11x\left(x-4\right)\left(-x+3\right)
Rewrite the complete factored expression.