Solve -11(2-b)<4(2b+2)=

$$- 11 ( 2 - b ) < 4 ( 2 b + 2 ) =$$

Solve for b

$$b<10$$

Solution Steps

Use the distributive property to multiply -11 by 2-b.

$$-22+11b<4\left(2b+2\right)$$

Use the distributive property to multiply 4 by 2b+2.

$$-22+11b<8b+8$$

Subtract 8b from both sides.

$$-22+11b-8b<8$$

Combine 11b and -8b to get 3b.

$$-22+3b<8$$

Add 22 to both sides.

$$3b<8+22$$

Add 8 and 22 to get 30.

$$3b<30$$

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$b<\frac{30}{3}$$

Divide 30 by 3 to get 10.

$$b<10$$