Solve -11+7-2{-4+1-[-2(-3+4)-2+(4+1)-8]-4}

$$- 11 + 7 - 2 \{ - 4 + 1 - [ - 2 ( - 3 + 4 ) - 2 + ( 4 + 1 ) - 8 ] - 4 \}$$

Evaluate

$$-4$$

Solution Steps

Add -11 and 7 to get -4.

$$-4-2\left(-4+1-\left(-2\left(-3+4\right)-2+4+1-8\right)-4\right)$$

Add -4 and 1 to get -3.

$$-4-2\left(-3-\left(-2\left(-3+4\right)-2+4+1-8\right)-4\right)$$

Add -3 and 4 to get 1.

$$-4-2\left(-3-\left(-2-2+4+1-8\right)-4\right)$$

Subtract 2 from -2 to get -4.

$$-4-2\left(-3-\left(-4+4+1-8\right)-4\right)$$

Add -4 and 4 to get 0.

$$-4-2\left(-3-\left(1-8\right)-4\right)$$

Subtract 8 from 1 to get -7.

$$-4-2\left(-3-\left(-7\right)-4\right)$$

The opposite of -7 is 7.

$$-4-2\left(-3+7-4\right)$$

Add -3 and 7 to get 4.

$$-4-2\left(4-4\right)$$

Subtract 4 from 4 to get 0.

$$-4-2\times 0$$

Multiply 2 and 0 to get 0.

$$-4-0$$

Subtract 0 from -4 to get -4.

$$-4$$

Factor

$$-4$$