Solve -10(-y+12)+11leq4y-49

$$- 10 ( - y + 12 ) + 11 \leq 4 y - 49$$

Solve for y

$$y\leq 10$$

Solution Steps

Use the distributive property to multiply -10 by -y+12.

$$-10\left(-y\right)-120+11\leq 4y-49$$

Multiply -10 and -1 to get 10.

$$10y-120+11\leq 4y-49$$

Add -120 and 11 to get -109.

$$10y-109\leq 4y-49$$

Subtract 4y from both sides.

$$10y-109-4y\leq -49$$

Combine 10y and -4y to get 6y.

$$6y-109\leq -49$$

Add 109 to both sides.

$$6y\leq -49+109$$

Add -49 and 109 to get 60.

$$6y\leq 60$$

Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.

$$y\leq \frac{60}{6}$$

Divide 60 by 6 to get 10.

$$y\leq 10$$