Solve -103/5-(-6/15)

$$- 10 \frac { 3 } { 5 } - ( - \frac { 6 } { 15 } )$$

Evaluate

$$-\frac{51}{5}=-10.2$$

Solution Steps

Multiply 10 and 5 to get 50.

$$-\frac{50+3}{5}-\left(-\frac{6}{15}\right)$$

Add 50 and 3 to get 53.

$$-\frac{53}{5}-\left(-\frac{6}{15}\right)$$

Reduce the fraction \frac{6}{15} to lowest terms by extracting and canceling out 3.

$$-\frac{53}{5}-\left(-\frac{2}{5}\right)$$

The opposite of -\frac{2}{5} is \frac{2}{5}.

$$-\frac{53}{5}+\frac{2}{5}$$

Since -\frac{53}{5} and \frac{2}{5} have the same denominator, add them by adding their numerators.

$$\frac{-53+2}{5}$$

Add -53 and 2 to get -51.

$$-\frac{51}{5}$$

Factor

$$-\frac{51}{5} = -10\frac{1}{5} = -10.2$$