Solve -10*[(-3)^3+(-2)^4+(-4608):(+96)]

$$- 10 \cdot [ ( - 3 ) ^ { 3 } + ( - 2 ) ^ { 4 } + ( - 4608 ) : ( + 96 ) ]$$

Evaluate

$$590$$

Solution Steps

Calculate -3 to the power of 3 and get -27.

$$-10\left(-27+\left(-2\right)^{4}+\frac{-4608}{96}\right)$$

Calculate -2 to the power of 4 and get 16.

$$-10\left(-27+16+\frac{-4608}{96}\right)$$

Add -27 and 16 to get -11.

$$-10\left(-11+\frac{-4608}{96}\right)$$

Divide -4608 by 96 to get -48.

$$-10\left(-11-48\right)$$

Subtract 48 from -11 to get -59.

$$-10\left(-59\right)$$

Multiply -10 and -59 to get 590.

$$590$$

Factor

$$2\times 5\times 59$$