Solve -10:-5+2^2-4*4^2+5^2-2

$$- 10 : - 5 + 2 ^ { 2 } - 4 \cdot 4 ^ { 2 } + 5 ^ { 2 } - 2$$

Evaluate

$$-35$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\frac{-10}{-5}+2^{2}-4^{3}+5^{2}-2$$

Divide -10 by -5 to get 2.

$$2+2^{2}-4^{3}+5^{2}-2$$

Calculate 2 to the power of 2 and get 4.

$$2+4-4^{3}+5^{2}-2$$

Add 2 and 4 to get 6.

$$6-4^{3}+5^{2}-2$$

Calculate 4 to the power of 3 and get 64.

$$6-64+5^{2}-2$$

Subtract 64 from 6 to get -58.

$$-58+5^{2}-2$$

Calculate 5 to the power of 2 and get 25.

$$-58+25-2$$

Add -58 and 25 to get -33.

$$-33-2$$

Subtract 2 from -33 to get -35.

$$-35$$

Factor

$$-35$$