Solve -10+8b-9-11b+4b-7

$$- 10 + 8 b - 9 - 11 b + 4 b - 7$$

Evaluate

$$b-26$$

Solution Steps

Subtract 9 from -10 to get -19.

$$-19+8b-11b+4b-7$$

Combine 8b and -11b to get -3b.

$$-19-3b+4b-7$$

Combine -3b and 4b to get b.

$$-19+b-7$$

Subtract 7 from -19 to get -26.

$$-26+b$$

Differentiate w.r.t. b

$$1$$

Steps Using Derivative Rule for Sum

Subtract 9 from -10 to get -19.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-19+8b-11b+4b-7)$$

Combine 8b and -11b to get -3b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-19-3b+4b-7)$$

Combine -3b and 4b to get b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-19+b-7)$$

Subtract 7 from -19 to get -26.

$$\frac{\mathrm{d}}{\mathrm{d}b}(-26+b)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$b^{1-1}$$

Subtract 1 from 1.

$$b^{0}$$

For any term t except 0, t^{0}=1.

$$1$$